In the given figure, AB = BC and AD = CD. Inradius ME = 5 cm, Inradius NF = 6 cm and Inradius HP = 8 cm.
What is the area of kite ABCD ?
In the given figure ABCD is a rectangle. E is point on AB such that incircle of triangle EBC touches EB, BC, and EC at point M, N and P respectively. OM = 2 cm . Bigger Circle touches AE, EC, DC and AD at points R, S, U and T respectively. G and F are two points on AD and H is a point on DC. EF and GH intersects at point Q, such that angle GQE is 90 degree. AE = AF.
What is the area of the rectangle?
ABCD is a Rhombus. A Circle through vertex A and C intersects AB at point E and CD at point F. EB = 119 cm and EF = 130 cm . What is the area of the rhombus ?